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8a^2+55a-7=0
a = 8; b = 55; c = -7;
Δ = b2-4ac
Δ = 552-4·8·(-7)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3249}=57$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-57}{2*8}=\frac{-112}{16} =-7 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+57}{2*8}=\frac{2}{16} =1/8 $
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